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5143001113 is a prime number
BaseRepresentation
bin1001100101000101…
…11111100000011001
3111021102110112012201
410302202333200121
541013102013423
62210200210201
7241306534225
oct46242774031
914242415181
105143001113
1121aa0a9948
12bb6469961
1363c679c33
1436b087785
152017a22ad
hex1328bf819

5143001113 has 2 divisors, whose sum is σ = 5143001114. Its totient is φ = 5143001112.

The previous prime is 5143001093. The next prime is 5143001131. The reversal of 5143001113 is 3111003415.

Together with next prime (5143001131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5128278544 + 14722569 = 71612^2 + 3837^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5143001113 is a prime.

It is not a weakly prime, because it can be changed into another prime (5143005113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2571500556 + 2571500557.

It is an arithmetic number, because the mean of its divisors is an integer number (2571500557).

Almost surely, 25143001113 is an apocalyptic number.

It is an amenable number.

5143001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5143001113 is an equidigital number, since it uses as much as digits as its factorization.

5143001113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 5143001113 is about 71714.7203369015. The cubic root of 5143001113 is about 1726.1248548520.

Adding to 5143001113 its reverse (3111003415), we get a palindrome (8254004528).

The spelling of 5143001113 in words is "five billion, one hundred forty-three million, one thousand, one hundred thirteen".