Base | Representation |
---|---|
bin | 111010011110010000001101… |
… | …0010110001100001000001011 |
3 | 2111110002121011012102222211222 |
4 | 1310330200122112030020023 |
5 | 1014403301114101430201 |
6 | 5021520322324512255 |
7 | 213223133466166310 |
oct | 16474403226141013 |
9 | 2443077135388758 |
10 | 514331365655051 |
11 | 13997778635961a |
12 | 49828a4584b68b |
13 | 190cb316723529 |
14 | 9101ab15a6d07 |
15 | 3e6de1494291b |
hex | 1d3c81a58c20b |
514331365655051 has 32 divisors (see below), whose sum is σ = 623278630719360. Its totient is φ = 414326625140736.
The previous prime is 514331365654961. The next prime is 514331365655131. The reversal of 514331365655051 is 150556563133415.
It is not a de Polignac number, because 514331365655051 - 226 = 514331298546187 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 514331365654984 and 514331365655002.
It is not an unprimeable number, because it can be changed into a prime (514331365615051) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 676160705 + ... + 676920941.
It is an arithmetic number, because the mean of its divisors is an integer number (19477457209980).
Almost surely, 2514331365655051 is an apocalyptic number.
514331365655051 is a deficient number, since it is larger than the sum of its proper divisors (108947265064309).
514331365655051 is a wasteful number, since it uses less digits than its factorization.
514331365655051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 768423.
The product of its (nonzero) digits is 12150000, while the sum is 53.
The spelling of 514331365655051 in words is "five hundred fourteen trillion, three hundred thirty-one billion, three hundred sixty-five million, six hundred fifty-five thousand, fifty-one".
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