Base | Representation |
---|---|
bin | 1110111110000001001… |
… | …10011001110101110011 |
3 | 1211011120201011010021121 |
4 | 13133000212121311303 |
5 | 31411323043313021 |
6 | 1032140412203111 |
7 | 52105431163132 |
oct | 7370046316563 |
9 | 1734521133247 |
10 | 514332401011 |
11 | 189144260510 |
12 | 83820a69497 |
13 | 39669590530 |
14 | 1ac72905919 |
15 | d5a4025741 |
hex | 77c0999d73 |
514332401011 has 64 divisors (see below), whose sum is σ = 654449886720. Its totient is φ = 397106012160.
The previous prime is 514332400997. The next prime is 514332401053. The reversal of 514332401011 is 110104233415.
It is not a de Polignac number, because 514332401011 - 25 = 514332400979 is a prime.
It is a super-2 number, since 2×5143324010112 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (514332402011) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 58000800 + ... + 58009666.
It is an arithmetic number, because the mean of its divisors is an integer number (10225779480).
Almost surely, 2514332401011 is an apocalyptic number.
514332401011 is a deficient number, since it is larger than the sum of its proper divisors (140117485709).
514332401011 is a wasteful number, since it uses less digits than its factorization.
514332401011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9524.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 514332401011 its reverse (110104233415), we get a palindrome (624436634426).
The spelling of 514332401011 in words is "five hundred fourteen billion, three hundred thirty-two million, four hundred one thousand, eleven".
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