Base | Representation |
---|---|
bin | 100101011011001000010… |
… | …1111000001101100011101 |
3 | 200012201021122101201212111 |
4 | 1022312100233001230131 |
5 | 1133232344022201000 |
6 | 14534520531234021 |
7 | 1040414553325606 |
oct | 112662057015435 |
9 | 20181248351774 |
10 | 5143504100125 |
11 | 1703390a78a16 |
12 | 6b0a19148911 |
13 | 2b40518c9b91 |
14 | 13ad3851cdad |
15 | 8dbdadaecba |
hex | 4ad90bc1b1d |
5143504100125 has 8 divisors (see below), whose sum is σ = 6419093117112. Its totient is φ = 4114803280000.
The previous prime is 5143504100117. The next prime is 5143504100143. The reversal of 5143504100125 is 5210014053415.
It can be written as a sum of positive squares in 4 ways, for example, as 1582833223449 + 3560670876676 = 1258107^2 + 1886974^2 .
It is not a de Polignac number, because 5143504100125 - 23 = 5143504100117 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20574016276 + ... + 20574016525.
It is an arithmetic number, because the mean of its divisors is an integer number (802386639639).
Almost surely, 25143504100125 is an apocalyptic number.
It is an amenable number.
5143504100125 is a deficient number, since it is larger than the sum of its proper divisors (1275589016987).
5143504100125 is an equidigital number, since it uses as much as digits as its factorization.
5143504100125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41148032816 (or 41148032806 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 5143504100125 in words is "five trillion, one hundred forty-three billion, five hundred four million, one hundred thousand, one hundred twenty-five".
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