Base | Representation |
---|---|
bin | 1110111110000011110… |
… | …01111111000011111101 |
3 | 1211011122020101021201021 |
4 | 13133001321333003331 |
5 | 31411344200431141 |
6 | 1032142513544141 |
7 | 52106115336646 |
oct | 7370171770375 |
9 | 1734566337637 |
10 | 514354311421 |
11 | 189155666095 |
12 | 83828275051 |
13 | 39670c92382 |
14 | 1ac757aa6cd |
15 | d5a5e026d1 |
hex | 77c1e7f0fd |
514354311421 has 4 divisors (see below), whose sum is σ = 514357515072. Its totient is φ = 514351107772.
The previous prime is 514354311319. The next prime is 514354311433. The reversal of 514354311421 is 124113453415.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 514354311421 - 211 = 514354309373 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (514354311461) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1347541 + ... + 1686586.
It is an arithmetic number, because the mean of its divisors is an integer number (128589378768).
Almost surely, 2514354311421 is an apocalyptic number.
It is an amenable number.
514354311421 is a deficient number, since it is larger than the sum of its proper divisors (3203651).
514354311421 is a wasteful number, since it uses less digits than its factorization.
514354311421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3203650.
The product of its digits is 28800, while the sum is 34.
Adding to 514354311421 its reverse (124113453415), we get a palindrome (638467764836).
The spelling of 514354311421 in words is "five hundred fourteen billion, three hundred fifty-four million, three hundred eleven thousand, four hundred twenty-one".
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