Base | Representation |
---|---|
bin | 10111011000111101111101… |
… | …10010110100000010111011 |
3 | 20202010011211212011002212011 |
4 | 23230132332302310002323 |
5 | 23220204232144023034 |
6 | 301221040133230351 |
7 | 13556042004240142 |
oct | 1354367662640273 |
9 | 222104755132764 |
10 | 51435434361019 |
11 | 15430710861265 |
12 | 5928646a923b7 |
13 | 2291457533077 |
14 | c9b6b9caa759 |
15 | 5e2e48a4e864 |
hex | 2ec7becb40bb |
51435434361019 has 2 divisors, whose sum is σ = 51435434361020. Its totient is φ = 51435434361018.
The previous prime is 51435434360971. The next prime is 51435434361061. The reversal of 51435434361019 is 91016343453415.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51435434361019 - 215 = 51435434328251 is a prime.
It is a super-3 number, since 3×514354343610193 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (51435434361319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25717717180509 + 25717717180510.
It is an arithmetic number, because the mean of its divisors is an integer number (25717717180510).
Almost surely, 251435434361019 is an apocalyptic number.
51435434361019 is a deficient number, since it is larger than the sum of its proper divisors (1).
51435434361019 is an equidigital number, since it uses as much as digits as its factorization.
51435434361019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2332800, while the sum is 49.
The spelling of 51435434361019 in words is "fifty-one trillion, four hundred thirty-five billion, four hundred thirty-four million, three hundred sixty-one thousand, nineteen".
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