Base | Representation |
---|---|
bin | 10111011000111101111101… |
… | …10010110100001010011001 |
3 | 20202010011211212011010111212 |
4 | 23230132332302310022121 |
5 | 23220204232144031442 |
6 | 301221040133232505 |
7 | 13556042004241424 |
oct | 1354367662641231 |
9 | 222104755133455 |
10 | 51435434361497 |
11 | 1543071086165a |
12 | 5928646a92735 |
13 | 2291457533354 |
14 | c9b6b9caa9bb |
15 | 5e2e48a4ea82 |
hex | 2ec7becb4299 |
51435434361497 has 2 divisors, whose sum is σ = 51435434361498. Its totient is φ = 51435434361496.
The previous prime is 51435434361449. The next prime is 51435434361551. The reversal of 51435434361497 is 79416343453415.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50747614597696 + 687819763801 = 7123736^2 + 829349^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51435434361497 is a prime.
It is a super-3 number, since 3×514354343614973 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (51435434361407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25717717180748 + 25717717180749.
It is an arithmetic number, because the mean of its divisors is an integer number (25717717180749).
Almost surely, 251435434361497 is an apocalyptic number.
It is an amenable number.
51435434361497 is a deficient number, since it is larger than the sum of its proper divisors (1).
51435434361497 is an equidigital number, since it uses as much as digits as its factorization.
51435434361497 is an evil number, because the sum of its binary digits is even.
The product of its digits is 65318400, while the sum is 59.
The spelling of 51435434361497 in words is "fifty-one trillion, four hundred thirty-five billion, four hundred thirty-four million, three hundred sixty-one thousand, four hundred ninety-seven".
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