Base | Representation |
---|---|
bin | 100101011011011000010… |
… | …1111101001100010011011 |
3 | 200012202200001220220011201 |
4 | 1022312300233221202123 |
5 | 1133234444012243420 |
6 | 14535050113535031 |
7 | 1040434064125663 |
oct | 112666057514233 |
9 | 20182601826151 |
10 | 5144041134235 |
11 | 170363712a663 |
12 | 6b0b48b74477 |
13 | 2b4108c4a843 |
14 | 13ad899951a3 |
15 | 8dc1d0e110a |
hex | 4adb0be989b |
5144041134235 has 32 divisors (see below), whose sum is σ = 6880304332800. Its totient is φ = 3669124032000.
The previous prime is 5144041134227. The next prime is 5144041134299. The reversal of 5144041134235 is 5324311404415.
It is a happy number.
It is not a de Polignac number, because 5144041134235 - 23 = 5144041134227 is a prime.
It is a super-2 number, since 2×51440411342352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5144041134194 and 5144041134203.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 37138860 + ... + 37277110.
It is an arithmetic number, because the mean of its divisors is an integer number (215009510400).
Almost surely, 25144041134235 is an apocalyptic number.
5144041134235 is a deficient number, since it is larger than the sum of its proper divisors (1736263198565).
5144041134235 is a wasteful number, since it uses less digits than its factorization.
5144041134235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 161331.
The product of its (nonzero) digits is 115200, while the sum is 37.
The spelling of 5144041134235 in words is "five trillion, one hundred forty-four billion, forty-one million, one hundred thirty-four thousand, two hundred thirty-five".
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