Base | Representation |
---|---|
bin | 101111111010001001… |
… | …010000000101101011 |
3 | 11220210001000022210121 |
4 | 233322021100011223 |
5 | 1320322442310301 |
6 | 35344251024111 |
7 | 3500523266023 |
oct | 577211200553 |
9 | 156701008717 |
10 | 51441369451 |
11 | 1a8a834827a |
12 | 9b7773b037 |
13 | 4b0a574464 |
14 | 26bdd30a83 |
15 | 15111ac3a1 |
hex | bfa25016b |
51441369451 has 2 divisors, whose sum is σ = 51441369452. Its totient is φ = 51441369450.
The previous prime is 51441369433. The next prime is 51441369461. The reversal of 51441369451 is 15496314415.
51441369451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51441369451 - 29 = 51441368939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51441369398 and 51441369407.
It is not a weakly prime, because it can be changed into another prime (51441369461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25720684725 + 25720684726.
It is an arithmetic number, because the mean of its divisors is an integer number (25720684726).
Almost surely, 251441369451 is an apocalyptic number.
51441369451 is a deficient number, since it is larger than the sum of its proper divisors (1).
51441369451 is an equidigital number, since it uses as much as digits as its factorization.
51441369451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 259200, while the sum is 43.
The spelling of 51441369451 in words is "fifty-one billion, four hundred forty-one million, three hundred sixty-nine thousand, four hundred fifty-one".
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