Base | Representation |
---|---|
bin | 100101011011101010101… |
… | …0000001111000101010011 |
3 | 200012211020202111020121221 |
4 | 1022313111100033011103 |
5 | 1133242222314001103 |
6 | 14535230554225511 |
7 | 1040455212360622 |
oct | 112672520170523 |
9 | 20184222436557 |
10 | 5144653656403 |
11 | 1703920960628 |
12 | 6b109a125297 |
13 | 2b41a5b0bcb1 |
14 | 13b00707b6b9 |
15 | 8dc56c841bd |
hex | 4add540f153 |
5144653656403 has 2 divisors, whose sum is σ = 5144653656404. Its totient is φ = 5144653656402.
The previous prime is 5144653656383. The next prime is 5144653656413. The reversal of 5144653656403 is 3046563564415.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5144653656403 - 29 = 5144653655891 is a prime.
It is a super-2 number, since 2×51446536564032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5144653656413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2572326828201 + 2572326828202.
It is an arithmetic number, because the mean of its divisors is an integer number (2572326828202).
Almost surely, 25144653656403 is an apocalyptic number.
5144653656403 is a deficient number, since it is larger than the sum of its proper divisors (1).
5144653656403 is an equidigital number, since it uses as much as digits as its factorization.
5144653656403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552000, while the sum is 52.
The spelling of 5144653656403 in words is "five trillion, one hundred forty-four billion, six hundred fifty-three million, six hundred fifty-six thousand, four hundred three".
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