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51450068742593 is a prime number
BaseRepresentation
bin10111011001011001001110…
…00100100011000111000001
320202011120121202022201100112
423230230213010203013001
523220424220044230333
6301231500231001105
713560100444362503
oct1354544704430701
9222146552281315
1051450068742593
1115436940560794
12592b44bb09195
13229294a3b7c51
14c9c2a7719d73
155e35036e2948
hex2ecb271231c1

51450068742593 has 2 divisors, whose sum is σ = 51450068742594. Its totient is φ = 51450068742592.

The previous prime is 51450068742533. The next prime is 51450068742643. The reversal of 51450068742593 is 39524786005415.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45172002304144 + 6278066438449 = 6721012^2 + 2505607^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51450068742593 is a prime.

It is not a weakly prime, because it can be changed into another prime (51450068742533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25725034371296 + 25725034371297.

It is an arithmetic number, because the mean of its divisors is an integer number (25725034371297).

It is a 2-persistent number, because it is pandigital, and so is 2⋅51450068742593 = 102900137485186, but 3⋅51450068742593 = 154350206227779 is not.

Almost surely, 251450068742593 is an apocalyptic number.

It is an amenable number.

51450068742593 is a deficient number, since it is larger than the sum of its proper divisors (1).

51450068742593 is an equidigital number, since it uses as much as digits as its factorization.

51450068742593 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36288000, while the sum is 59.

The spelling of 51450068742593 in words is "fifty-one trillion, four hundred fifty billion, sixty-eight million, seven hundred forty-two thousand, five hundred ninety-three".