Base | Representation |
---|---|
bin | 101111111010110001… |
… | …110010001101001001 |
3 | 11220210210000011020201 |
4 | 233322301302031021 |
5 | 1320333202314303 |
6 | 35345310452201 |
7 | 3501012512122 |
oct | 577261621511 |
9 | 156723004221 |
10 | 51451994953 |
11 | 1a903345387 |
12 | 9b7b204061 |
13 | 4b0c824938 |
14 | 26c14d9049 |
15 | 15120aa81d |
hex | bfac72349 |
51451994953 has 2 divisors, whose sum is σ = 51451994954. Its totient is φ = 51451994952.
The previous prime is 51451994939. The next prime is 51451994981. The reversal of 51451994953 is 35949915415.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50367478329 + 1084516624 = 224427^2 + 32932^2 .
It is a cyclic number.
It is not a de Polignac number, because 51451994953 - 221 = 51449897801 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51451994894 and 51451994903.
It is not a weakly prime, because it can be changed into another prime (51451994933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25725997476 + 25725997477.
It is an arithmetic number, because the mean of its divisors is an integer number (25725997477).
Almost surely, 251451994953 is an apocalyptic number.
It is an amenable number.
51451994953 is a deficient number, since it is larger than the sum of its proper divisors (1).
51451994953 is an equidigital number, since it uses as much as digits as its factorization.
51451994953 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4374000, while the sum is 55.
The spelling of 51451994953 in words is "fifty-one billion, four hundred fifty-one million, nine hundred ninety-four thousand, nine hundred fifty-three".
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