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5145242344433 is a prime number
BaseRepresentation
bin100101011011111100001…
…0101111001101111110001
3200012212202210012200210022
41022313320111321233301
51133244424020010213
614535405224013225
71040505621214352
oct112677025715761
920185683180708
105145242344433
1117040a3192664
126b1223301215
132b426aa76ac9
1413b06131bd29
158dc8d7ba308
hex4adf8579bf1

5145242344433 has 2 divisors, whose sum is σ = 5145242344434. Its totient is φ = 5145242344432.

The previous prime is 5145242344427. The next prime is 5145242344471. The reversal of 5145242344433 is 3344432425415.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5078749017664 + 66493326769 = 2253608^2 + 257863^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5145242344433 is a prime.

It is not a weakly prime, because it can be changed into another prime (5145242344423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2572621172216 + 2572621172217.

It is an arithmetic number, because the mean of its divisors is an integer number (2572621172217).

Almost surely, 25145242344433 is an apocalyptic number.

It is an amenable number.

5145242344433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5145242344433 is an equidigital number, since it uses as much as digits as its factorization.

5145242344433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2764800, while the sum is 44.

Adding to 5145242344433 its reverse (3344432425415), we get a palindrome (8489674769848).

The spelling of 5145242344433 in words is "five trillion, one hundred forty-five billion, two hundred forty-two million, three hundred forty-four thousand, four hundred thirty-three".