Base | Representation |
---|---|
bin | 10111011001011101110010… |
… | …10100111001001111111001 |
3 | 20202011210221202111120020201 |
4 | 23230232321110321033321 |
5 | 23220444231230013423 |
6 | 301232543523322201 |
7 | 13560215321106436 |
oct | 1354567124711771 |
9 | 222153852446221 |
10 | 51452522501113 |
11 | 1543798a650898 |
12 | 592ba15820361 |
13 | 2292c4b876976 |
14 | c9c45b570b8d |
15 | 5e35e8d372ad |
hex | 2ecbb95393f9 |
51452522501113 has 2 divisors, whose sum is σ = 51452522501114. Its totient is φ = 51452522501112.
The previous prime is 51452522501069. The next prime is 51452522501137. The reversal of 51452522501113 is 31110522525415.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51449231987344 + 3290513769 = 7172812^2 + 57363^2 .
It is a cyclic number.
It is not a de Polignac number, because 51452522501113 - 29 = 51452522500601 is a prime.
It is not a weakly prime, because it can be changed into another prime (51452522502113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25726261250556 + 25726261250557.
It is an arithmetic number, because the mean of its divisors is an integer number (25726261250557).
Almost surely, 251452522501113 is an apocalyptic number.
It is an amenable number.
51452522501113 is a deficient number, since it is larger than the sum of its proper divisors (1).
51452522501113 is an equidigital number, since it uses as much as digits as its factorization.
51452522501113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60000, while the sum is 37.
The spelling of 51452522501113 in words is "fifty-one trillion, four hundred fifty-two billion, five hundred twenty-two million, five hundred one thousand, one hundred thirteen".
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