Base | Representation |
---|---|
bin | 10111011001100000111110… |
… | …10111110010011001000011 |
3 | 20202011222101001222220220101 |
4 | 23230300133113302121003 |
5 | 23221011233020113431 |
6 | 301233425442223231 |
7 | 13560305620133344 |
oct | 1354603727623103 |
9 | 222158331886811 |
10 | 51454234535491 |
11 | 15438688a93637 |
12 | 5930213054b17 |
13 | 2293162477a68 |
14 | c9c580aaa0cb |
15 | 5e36992b6961 |
hex | 2ecc1f5f2643 |
51454234535491 has 2 divisors, whose sum is σ = 51454234535492. Its totient is φ = 51454234535490.
The previous prime is 51454234535479. The next prime is 51454234535533. The reversal of 51454234535491 is 19453543245415.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51454234535491 - 231 = 51452087051843 is a prime.
It is a super-2 number, since 2×514542345354912 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51454234535441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25727117267745 + 25727117267746.
It is an arithmetic number, because the mean of its divisors is an integer number (25727117267746).
Almost surely, 251454234535491 is an apocalyptic number.
51454234535491 is a deficient number, since it is larger than the sum of its proper divisors (1).
51454234535491 is an equidigital number, since it uses as much as digits as its factorization.
51454234535491 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 25920000, while the sum is 55.
The spelling of 51454234535491 in words is "fifty-one trillion, four hundred fifty-four billion, two hundred thirty-four million, five hundred thirty-five thousand, four hundred ninety-one".
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