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514664077153001 is a prime number
BaseRepresentation
bin111010100000101011001000…
…1011111110101001011101001
32111111021101221102211021220012
41311001112101133311023221
51014424224012222344001
65022333225114541305
7213256152420232436
oct16501262137651351
92444241842737805
10514664077153001
11139a9589a319446
124988141a137835
13191237ca5c8289
149113c34cdab8d
153e778d8cd22bb
hex1d415917f52e9

514664077153001 has 2 divisors, whose sum is σ = 514664077153002. Its totient is φ = 514664077153000.

The previous prime is 514664077152989. The next prime is 514664077153087. The reversal of 514664077153001 is 100351770466415.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 354250706759401 + 160413370393600 = 18821549^2 + 12665440^2 .

It is a cyclic number.

It is not a de Polignac number, because 514664077153001 - 210 = 514664077151977 is a prime.

It is a super-2 number, since 2×5146640771530012 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (514664077156001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257332038576500 + 257332038576501.

It is an arithmetic number, because the mean of its divisors is an integer number (257332038576501).

Almost surely, 2514664077153001 is an apocalyptic number.

It is an amenable number.

514664077153001 is a deficient number, since it is larger than the sum of its proper divisors (1).

514664077153001 is an equidigital number, since it uses as much as digits as its factorization.

514664077153001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2116800, while the sum is 50.

The spelling of 514664077153001 in words is "five hundred fourteen trillion, six hundred sixty-four billion, seventy-seven million, one hundred fifty-three thousand, one".