Base | Representation |
---|---|
bin | 111010100000101011001000… |
… | …1011111110101001011101001 |
3 | 2111111021101221102211021220012 |
4 | 1311001112101133311023221 |
5 | 1014424224012222344001 |
6 | 5022333225114541305 |
7 | 213256152420232436 |
oct | 16501262137651351 |
9 | 2444241842737805 |
10 | 514664077153001 |
11 | 139a9589a319446 |
12 | 4988141a137835 |
13 | 191237ca5c8289 |
14 | 9113c34cdab8d |
15 | 3e778d8cd22bb |
hex | 1d415917f52e9 |
514664077153001 has 2 divisors, whose sum is σ = 514664077153002. Its totient is φ = 514664077153000.
The previous prime is 514664077152989. The next prime is 514664077153087. The reversal of 514664077153001 is 100351770466415.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 354250706759401 + 160413370393600 = 18821549^2 + 12665440^2 .
It is a cyclic number.
It is not a de Polignac number, because 514664077153001 - 210 = 514664077151977 is a prime.
It is a super-2 number, since 2×5146640771530012 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (514664077156001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257332038576500 + 257332038576501.
It is an arithmetic number, because the mean of its divisors is an integer number (257332038576501).
Almost surely, 2514664077153001 is an apocalyptic number.
It is an amenable number.
514664077153001 is a deficient number, since it is larger than the sum of its proper divisors (1).
514664077153001 is an equidigital number, since it uses as much as digits as its factorization.
514664077153001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2116800, while the sum is 50.
The spelling of 514664077153001 in words is "five hundred fourteen trillion, six hundred sixty-four billion, seventy-seven million, one hundred fifty-three thousand, one".
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