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51472021 = 491104831
BaseRepresentation
bin1100010001011…
…0011010010101
310120212001100011
43010112122111
5101134101041
65035120221
71163335126
oct304263225
9116761304
1051472021
1127066767
12152a3071
13a882423
146b9c04d
1547bae81
hex3116695

51472021 has 4 divisors (see below), whose sum is σ = 51577344. Its totient is φ = 51366700.

The previous prime is 51472019. The next prime is 51472037. The reversal of 51472021 is 12027415.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51472021 - 21 = 51472019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51471983 and 51472001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51472051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51925 + ... + 52906.

It is an arithmetic number, because the mean of its divisors is an integer number (12894336).

Almost surely, 251472021 is an apocalyptic number.

It is an amenable number.

51472021 is a deficient number, since it is larger than the sum of its proper divisors (105323).

51472021 is a wasteful number, since it uses less digits than its factorization.

51472021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105322.

The product of its (nonzero) digits is 560, while the sum is 22.

The square root of 51472021 is about 7174.4003930642. The cubic root of 51472021 is about 371.9835546937.

Adding to 51472021 its reverse (12027415), we get a palindrome (63499436).

The spelling of 51472021 in words is "fifty-one million, four hundred seventy-two thousand, twenty-one".

Divisors: 1 491 104831 51472021