Base | Representation |
---|---|
bin | 10111011010001110001111… |
… | …11110010011011111000011 |
3 | 20202021022002211022221021112 |
4 | 23231013013332103133003 |
5 | 23221411021214310113 |
6 | 301252525222513535 |
7 | 13562126106414353 |
oct | 1355070776233703 |
9 | 222238084287245 |
10 | 51478538041283 |
11 | 15447a1a755211 |
12 | 5934a762958ab |
13 | 22955365cb812 |
14 | c9d80874cb63 |
15 | 5e411cc5a5a8 |
hex | 2ed1c7f937c3 |
51478538041283 has 2 divisors, whose sum is σ = 51478538041284. Its totient is φ = 51478538041282.
The previous prime is 51478538041241. The next prime is 51478538041327. The reversal of 51478538041283 is 38214083587415.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51478538041283 - 26 = 51478538041219 is a prime.
It is not a weakly prime, because it can be changed into another prime (51478538041223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25739269020641 + 25739269020642.
It is an arithmetic number, because the mean of its divisors is an integer number (25739269020642).
Almost surely, 251478538041283 is an apocalyptic number.
51478538041283 is a deficient number, since it is larger than the sum of its proper divisors (1).
51478538041283 is an equidigital number, since it uses as much as digits as its factorization.
51478538041283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25804800, while the sum is 59.
The spelling of 51478538041283 in words is "fifty-one trillion, four hundred seventy-eight billion, five hundred thirty-eight million, forty-one thousand, two hundred eighty-three".
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