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514941228283 is a prime number
BaseRepresentation
bin1110111111001001110…
…00111001010011111011
31211020011010202202021211
413133210320321103323
531414044423301113
61032321041343551
752126503135556
oct7374470712373
91736133682254
10514941228283
11189426998449
1283970937bb7
1339735759c61
141accd70969d
15d5dc6d8b3d
hex77e4e394fb

514941228283 has 2 divisors, whose sum is σ = 514941228284. Its totient is φ = 514941228282.

The previous prime is 514941228251. The next prime is 514941228293. The reversal of 514941228283 is 382822149415.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 514941228283 - 25 = 514941228251 is a prime.

It is not a weakly prime, because it can be changed into another prime (514941228223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257470614141 + 257470614142.

It is an arithmetic number, because the mean of its divisors is an integer number (257470614142).

Almost surely, 2514941228283 is an apocalyptic number.

514941228283 is a deficient number, since it is larger than the sum of its proper divisors (1).

514941228283 is an equidigital number, since it uses as much as digits as its factorization.

514941228283 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1105920, while the sum is 49.

The spelling of 514941228283 in words is "five hundred fourteen billion, nine hundred forty-one million, two hundred twenty-eight thousand, two hundred eighty-three".