Base | Representation |
---|---|
bin | 10111011011010000011111… |
… | …10101001100100001001011 |
3 | 20202101200220102201212212111 |
4 | 23231220033311030201023 |
5 | 23223001340424220441 |
6 | 301321130302523151 |
7 | 13564525334516143 |
oct | 1355501765144113 |
9 | 222350812655774 |
10 | 51514103351371 |
11 | 15461010410071 |
12 | 593b940b964b7 |
13 | 22989b39934bb |
14 | ca141dd71923 |
15 | 5e5000255081 |
hex | 2eda0fd4c84b |
51514103351371 has 2 divisors, whose sum is σ = 51514103351372. Its totient is φ = 51514103351370.
The previous prime is 51514103351297. The next prime is 51514103351401. The reversal of 51514103351371 is 17315330141515.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51514103351371 - 217 = 51514103220299 is a prime.
It is not a weakly prime, because it can be changed into another prime (51514103951371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25757051675685 + 25757051675686.
It is an arithmetic number, because the mean of its divisors is an integer number (25757051675686).
Almost surely, 251514103351371 is an apocalyptic number.
51514103351371 is a deficient number, since it is larger than the sum of its proper divisors (1).
51514103351371 is an equidigital number, since it uses as much as digits as its factorization.
51514103351371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 94500, while the sum is 40.
Adding to 51514103351371 its reverse (17315330141515), we get a palindrome (68829433492886).
The spelling of 51514103351371 in words is "fifty-one trillion, five hundred fourteen billion, one hundred three million, three hundred fifty-one thousand, three hundred seventy-one".
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