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5152117101 = 31717372367
BaseRepresentation
bin1001100110001011…
…10001000101101101
3111022001121122222220
410303011301011231
541022420221401
62211123425553
7241450162365
oct46305610555
914261548886
105152117101
11220426591a
12bb95252b9
1364151c301
1436c37b9a5
152024a3336
hex13317116d

5152117101 has 4 divisors (see below), whose sum is σ = 6869489472. Its totient is φ = 3434744732.

The previous prime is 5152117079. The next prime is 5152117127. The reversal of 5152117101 is 1017112515.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5152117101 - 27 = 5152116973 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5152117171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 858686181 + ... + 858686186.

It is an arithmetic number, because the mean of its divisors is an integer number (1717372368).

Almost surely, 25152117101 is an apocalyptic number.

It is an amenable number.

5152117101 is a deficient number, since it is larger than the sum of its proper divisors (1717372371).

5152117101 is a wasteful number, since it uses less digits than its factorization.

5152117101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1717372370.

The product of its (nonzero) digits is 350, while the sum is 24.

The square root of 5152117101 is about 71778.2494980199. The cubic root of 5152117101 is about 1727.1441070541.

Adding to 5152117101 its reverse (1017112515), we get a palindrome (6169229616).

The spelling of 5152117101 in words is "five billion, one hundred fifty-two million, one hundred seventeen thousand, one hundred one".

Divisors: 1 3 1717372367 5152117101