Base | Representation |
---|---|
bin | 10111011100000101000101… |
… | …00010000111011000100011 |
3 | 20202111101202220102221211011 |
4 | 23232002202202013120203 |
5 | 23223432200101413011 |
6 | 301342115504201351 |
7 | 13566545044512334 |
oct | 1356024242073043 |
9 | 222441686387734 |
10 | 51542334404131 |
11 | 15471a8807992a |
12 | 59452bb609257 |
13 | 229b56271b74c |
14 | ca293b4a828b |
15 | 5e5b0390b621 |
hex | 2ee0a2887623 |
51542334404131 has 2 divisors, whose sum is σ = 51542334404132. Its totient is φ = 51542334404130.
The previous prime is 51542334404069. The next prime is 51542334404147. The reversal of 51542334404131 is 13140443324515.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51542334404131 is a prime.
It is a super-2 number, since 2×515423344041312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51542334404191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25771167202065 + 25771167202066.
It is an arithmetic number, because the mean of its divisors is an integer number (25771167202066).
Almost surely, 251542334404131 is an apocalyptic number.
51542334404131 is a deficient number, since it is larger than the sum of its proper divisors (1).
51542334404131 is an equidigital number, since it uses as much as digits as its factorization.
51542334404131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 40.
Adding to 51542334404131 its reverse (13140443324515), we get a palindrome (64682777728646).
The spelling of 51542334404131 in words is "fifty-one trillion, five hundred forty-two billion, three hundred thirty-four million, four hundred four thousand, one hundred thirty-one".
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