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51554021234201 is a prime number
BaseRepresentation
bin10111011100011010110110…
…00111110101011000011001
320202112111221101021102210022
423232031123013311120121
523224130113413443301
6301351331305400225
713600440464105243
oct1356153307653031
9222474841242708
1051554021234201
1115476a34a81282
125947621499075
13229c6a5a23b05
14ca3329685093
155e608991ad1b
hex2ee35b1f5619

51554021234201 has 2 divisors, whose sum is σ = 51554021234202. Its totient is φ = 51554021234200.

The previous prime is 51554021234081. The next prime is 51554021234311. The reversal of 51554021234201 is 10243212045515.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49261461859801 + 2292559374400 = 7018651^2 + 1514120^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51554021234201 is a prime.

It is not a weakly prime, because it can be changed into another prime (51554021234801) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25777010617100 + 25777010617101.

It is an arithmetic number, because the mean of its divisors is an integer number (25777010617101).

Almost surely, 251554021234201 is an apocalyptic number.

It is an amenable number.

51554021234201 is a deficient number, since it is larger than the sum of its proper divisors (1).

51554021234201 is an equidigital number, since it uses as much as digits as its factorization.

51554021234201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48000, while the sum is 35.

Adding to 51554021234201 its reverse (10243212045515), we get a palindrome (61797233279716).

The spelling of 51554021234201 in words is "fifty-one trillion, five hundred fifty-four billion, twenty-one million, two hundred thirty-four thousand, two hundred one".