Base | Representation |
---|---|
bin | 10111011100011010110110… |
… | …00111110101011000011001 |
3 | 20202112111221101021102210022 |
4 | 23232031123013311120121 |
5 | 23224130113413443301 |
6 | 301351331305400225 |
7 | 13600440464105243 |
oct | 1356153307653031 |
9 | 222474841242708 |
10 | 51554021234201 |
11 | 15476a34a81282 |
12 | 5947621499075 |
13 | 229c6a5a23b05 |
14 | ca3329685093 |
15 | 5e608991ad1b |
hex | 2ee35b1f5619 |
51554021234201 has 2 divisors, whose sum is σ = 51554021234202. Its totient is φ = 51554021234200.
The previous prime is 51554021234081. The next prime is 51554021234311. The reversal of 51554021234201 is 10243212045515.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49261461859801 + 2292559374400 = 7018651^2 + 1514120^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51554021234201 is a prime.
It is not a weakly prime, because it can be changed into another prime (51554021234801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25777010617100 + 25777010617101.
It is an arithmetic number, because the mean of its divisors is an integer number (25777010617101).
Almost surely, 251554021234201 is an apocalyptic number.
It is an amenable number.
51554021234201 is a deficient number, since it is larger than the sum of its proper divisors (1).
51554021234201 is an equidigital number, since it uses as much as digits as its factorization.
51554021234201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48000, while the sum is 35.
Adding to 51554021234201 its reverse (10243212045515), we get a palindrome (61797233279716).
The spelling of 51554021234201 in words is "fifty-one trillion, five hundred fifty-four billion, twenty-one million, two hundred thirty-four thousand, two hundred one".
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