Base | Representation |
---|---|
bin | 1111000000010001011… |
… | …10101100101101010001 |
3 | 1211021201001020022000201 |
4 | 13200020232230231101 |
5 | 31421312342104433 |
6 | 1032500441415201 |
7 | 52150424146423 |
oct | 7401056545521 |
9 | 1737631208021 |
10 | 515542534993 |
11 | 189705359042 |
12 | 83aba19a501 |
13 | 398001c2545 |
14 | 1ad49512813 |
15 | d6253b3a7d |
hex | 7808bacb51 |
515542534993 has 2 divisors, whose sum is σ = 515542534994. Its totient is φ = 515542534992.
The previous prime is 515542534981. The next prime is 515542535077. The reversal of 515542534993 is 399435245515.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 447605155089 + 67937379904 = 669033^2 + 260648^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-515542534993 is a prime.
It is not a weakly prime, because it can be changed into another prime (515542532993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257771267496 + 257771267497.
It is an arithmetic number, because the mean of its divisors is an integer number (257771267497).
Almost surely, 2515542534993 is an apocalyptic number.
It is an amenable number.
515542534993 is a deficient number, since it is larger than the sum of its proper divisors (1).
515542534993 is an equidigital number, since it uses as much as digits as its factorization.
515542534993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14580000, while the sum is 55.
The spelling of 515542534993 in words is "five hundred fifteen billion, five hundred forty-two million, five hundred thirty-four thousand, nine hundred ninety-three".
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