Base | Representation |
---|---|
bin | 10111011100011100111011… |
… | …11110101101010100100011 |
3 | 20202112121211112220202002001 |
4 | 23232032131332231110203 |
5 | 23224134413041242423 |
6 | 301352034455104431 |
7 | 13600510334201563 |
oct | 1356163576552443 |
9 | 222477745822061 |
10 | 51555142915363 |
11 | 154774601549aa |
12 | 5947895072117 |
13 | 229c824226189 |
14 | ca33d4628da3 |
15 | 5e6103135cad |
hex | 2ee39dfad523 |
51555142915363 has 2 divisors, whose sum is σ = 51555142915364. Its totient is φ = 51555142915362.
The previous prime is 51555142915337. The next prime is 51555142915379. The reversal of 51555142915363 is 36351924155515.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51555142915363 - 29 = 51555142914851 is a prime.
It is a super-3 number, since 3×515551429153633 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (51555142915663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25777571457681 + 25777571457682.
It is an arithmetic number, because the mean of its divisors is an integer number (25777571457682).
Almost surely, 251555142915363 is an apocalyptic number.
51555142915363 is a deficient number, since it is larger than the sum of its proper divisors (1).
51555142915363 is an equidigital number, since it uses as much as digits as its factorization.
51555142915363 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12150000, while the sum is 55.
The spelling of 51555142915363 in words is "fifty-one trillion, five hundred fifty-five billion, one hundred forty-two million, nine hundred fifteen thousand, three hundred sixty-three".
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