Base | Representation |
---|---|
bin | 100101100001110000011… |
… | …0110010010100001101001 |
3 | 200021002000021201222020011 |
4 | 1023003200312102201221 |
5 | 1134001014132130431 |
6 | 14545232503531521 |
7 | 1041430301563444 |
oct | 113034066224151 |
9 | 20232007658204 |
10 | 5157733083241 |
11 | 17094229555a2 |
12 | 6b372a459ba1 |
13 | 2b54ab7a020b |
14 | 13b8c81a065b |
15 | 8e270174cb1 |
hex | 4b0e0d92869 |
5157733083241 has 2 divisors, whose sum is σ = 5157733083242. Its totient is φ = 5157733083240.
The previous prime is 5157733083197. The next prime is 5157733083311. The reversal of 5157733083241 is 1423803377515.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4874363177616 + 283369905625 = 2207796^2 + 532325^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5157733083241 is a prime.
It is not a weakly prime, because it can be changed into another prime (5157733083641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2578866541620 + 2578866541621.
It is an arithmetic number, because the mean of its divisors is an integer number (2578866541621).
Almost surely, 25157733083241 is an apocalyptic number.
It is an amenable number.
5157733083241 is a deficient number, since it is larger than the sum of its proper divisors (1).
5157733083241 is an equidigital number, since it uses as much as digits as its factorization.
5157733083241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2116800, while the sum is 49.
The spelling of 5157733083241 in words is "five trillion, one hundred fifty-seven billion, seven hundred thirty-three million, eighty-three thousand, two hundred forty-one".
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