Base | Representation |
---|---|
bin | 10111011110001101101001… |
… | …10101110011111000101011 |
3 | 20202202102000210222000002111 |
4 | 23233012310311303320223 |
5 | 23231132330414013232 |
6 | 301435523252343151 |
7 | 13605052034014144 |
oct | 1357066465637053 |
9 | 222672023860074 |
10 | 51615656001067 |
11 | 154a0093216934 |
12 | 5957562914ab7 |
13 | 22a544906a672 |
14 | ca62d52bcacb |
15 | 5e7995939047 |
hex | 2ef1b4d73e2b |
51615656001067 has 2 divisors, whose sum is σ = 51615656001068. Its totient is φ = 51615656001066.
The previous prime is 51615656001061. The next prime is 51615656001103. The reversal of 51615656001067 is 76010065651615.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51615656001067 - 23 = 51615656001059 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 51615656001067.
It is not a weakly prime, because it can be changed into another prime (51615656001061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25807828000533 + 25807828000534.
It is an arithmetic number, because the mean of its divisors is an integer number (25807828000534).
Almost surely, 251615656001067 is an apocalyptic number.
51615656001067 is a deficient number, since it is larger than the sum of its proper divisors (1).
51615656001067 is an equidigital number, since it uses as much as digits as its factorization.
51615656001067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134000, while the sum is 49.
The spelling of 51615656001067 in words is "fifty-one trillion, six hundred fifteen billion, six hundred fifty-six million, one thousand, sixty-seven".
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