Base | Representation |
---|---|
bin | 110000000110111100… |
… | …100000110111110001 |
3 | 11221100000010111112221 |
4 | 300012330200313301 |
5 | 1321242432243004 |
6 | 35421442121041 |
7 | 3506041616065 |
oct | 600674406761 |
9 | 157300114487 |
10 | 51656134129 |
11 | 1a9a85a5146 |
12 | a017650181 |
13 | 4b42bcac52 |
14 | 2700677aa5 |
15 | 1524e81354 |
hex | c06f20df1 |
51656134129 has 2 divisors, whose sum is σ = 51656134130. Its totient is φ = 51656134128.
The previous prime is 51656134109. The next prime is 51656134133. The reversal of 51656134129 is 92143165615.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 26732250000 + 24923884129 = 163500^2 + 157873^2 .
It is a cyclic number.
It is not a de Polignac number, because 51656134129 - 221 = 51654036977 is a prime.
It is not a weakly prime, because it can be changed into another prime (51656134109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25828067064 + 25828067065.
It is an arithmetic number, because the mean of its divisors is an integer number (25828067065).
Almost surely, 251656134129 is an apocalyptic number.
It is an amenable number.
51656134129 is a deficient number, since it is larger than the sum of its proper divisors (1).
51656134129 is an equidigital number, since it uses as much as digits as its factorization.
51656134129 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 194400, while the sum is 43.
The spelling of 51656134129 in words is "fifty-one billion, six hundred fifty-six million, one hundred thirty-four thousand, one hundred twenty-nine".
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