Base | Representation |
---|---|
bin | 111010101110100100011001… |
… | …0101010000011011101010001 |
3 | 2111202000222010120111200102121 |
4 | 1311131020302222003131101 |
5 | 1020202021013042202423 |
6 | 5030354411503214241 |
7 | 213544135666334221 |
oct | 16535106252033521 |
9 | 2452028116450377 |
10 | 516573746444113 |
11 | 13a6617718aa706 |
12 | 49b2b5525a7381 |
13 | 19231906679a37 |
14 | 917c4349a4081 |
15 | 3eac4068aa45d |
hex | 1d5d232a83751 |
516573746444113 has 2 divisors, whose sum is σ = 516573746444114. Its totient is φ = 516573746444112.
The previous prime is 516573746444059. The next prime is 516573746444137. The reversal of 516573746444113 is 311444647375615.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 361124916804369 + 155448829639744 = 19003287^2 + 12467912^2 .
It is a cyclic number.
It is not a de Polignac number, because 516573746444113 - 237 = 516436307490641 is a prime.
It is not a weakly prime, because it can be changed into another prime (516573746444143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258286873222056 + 258286873222057.
It is an arithmetic number, because the mean of its divisors is an integer number (258286873222057).
Almost surely, 2516573746444113 is an apocalyptic number.
It is an amenable number.
516573746444113 is a deficient number, since it is larger than the sum of its proper divisors (1).
516573746444113 is an equidigital number, since it uses as much as digits as its factorization.
516573746444113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 101606400, while the sum is 61.
The spelling of 516573746444113 in words is "five hundred sixteen trillion, five hundred seventy-three billion, seven hundred forty-six million, four hundred forty-four thousand, one hundred thirteen".
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