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51660155101651 is a prime number
BaseRepresentation
bin10111011111100000100010…
…01100011010000111010011
320202220122220000212112022221
423233300101030122013103
523232344444201223101
6301512203030441511
713611215542101235
oct1357602114320723
9222818800775287
1051660155101651
1115507a48860818
125964101503297
1322a96bb270205
14ca8517200255
155e8bec3d2aa1
hex2efc1131a1d3

51660155101651 has 2 divisors, whose sum is σ = 51660155101652. Its totient is φ = 51660155101650.

The previous prime is 51660155101637. The next prime is 51660155101843. The reversal of 51660155101651 is 15610155106615.

51660155101651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 51660155101651 - 27 = 51660155101523 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51660155101598 and 51660155101607.

It is not a weakly prime, because it can be changed into another prime (51660155101601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25830077550825 + 25830077550826.

It is an arithmetic number, because the mean of its divisors is an integer number (25830077550826).

Almost surely, 251660155101651 is an apocalyptic number.

51660155101651 is a deficient number, since it is larger than the sum of its proper divisors (1).

51660155101651 is an equidigital number, since it uses as much as digits as its factorization.

51660155101651 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135000, while the sum is 43.

The spelling of 51660155101651 in words is "fifty-one trillion, six hundred sixty billion, one hundred fifty-five million, one hundred one thousand, six hundred fifty-one".