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51660820552793 is a prime number
BaseRepresentation
bin10111011111100001110001…
…10110111001110001011001
320202220201121102000221200112
423233300320312321301121
523232402330030142133
6301512353041414105
713611241202250104
oct1357607066716131
9222821542027615
1051660820552793
111550825a453041
12596426833a335
1322a97960a3c9a
14ca857b74373b
155e8c3aa2d648
hex2efc38db9c59

51660820552793 has 2 divisors, whose sum is σ = 51660820552794. Its totient is φ = 51660820552792.

The previous prime is 51660820552711. The next prime is 51660820552837. The reversal of 51660820552793 is 39725502806615.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50101311619984 + 1559508932809 = 7078228^2 + 1248803^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51660820552793 is a prime.

It is a super-2 number, since 2×516608205527932 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51660820554793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25830410276396 + 25830410276397.

It is an arithmetic number, because the mean of its divisors is an integer number (25830410276397).

Almost surely, 251660820552793 is an apocalyptic number.

It is an amenable number.

51660820552793 is a deficient number, since it is larger than the sum of its proper divisors (1).

51660820552793 is an equidigital number, since it uses as much as digits as its factorization.

51660820552793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27216000, while the sum is 59.

The spelling of 51660820552793 in words is "fifty-one trillion, six hundred sixty billion, eight hundred twenty million, five hundred fifty-two thousand, seven hundred ninety-three".