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516661970113 is a prime number
BaseRepresentation
bin1111000010010110111…
…01000000010011000001
31211101121001122111022201
413201023131000103001
531431110431020423
61033203511033201
752220236166602
oct7411335002301
91741531574281
10516661970113
1118a12a238233
128417106b801
133994b0b94a3
141b01406dda9
15d68d7d82ad
hex784b7404c1

516661970113 has 2 divisors, whose sum is σ = 516661970114. Its totient is φ = 516661970112.

The previous prime is 516661970089. The next prime is 516661970117. The reversal of 516661970113 is 311079166615.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 480549809089 + 36112161024 = 693217^2 + 190032^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-516661970113 is a prime.

It is a super-2 number, since 2×5166619701132 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (516661970117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258330985056 + 258330985057.

It is an arithmetic number, because the mean of its divisors is an integer number (258330985057).

Almost surely, 2516661970113 is an apocalyptic number.

It is an amenable number.

516661970113 is a deficient number, since it is larger than the sum of its proper divisors (1).

516661970113 is an equidigital number, since it uses as much as digits as its factorization.

516661970113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 204120, while the sum is 46.

The spelling of 516661970113 in words is "five hundred sixteen billion, six hundred sixty-one million, nine hundred seventy thousand, one hundred thirteen".