Base | Representation |
---|---|
bin | 1111000010100111100… |
… | …01001100010111010101 |
3 | 1211101221210011100010002 |
4 | 13201103301030113111 |
5 | 31431402134331044 |
6 | 1033225413141045 |
7 | 52223552046443 |
oct | 7412361142725 |
9 | 1741853140102 |
10 | 516801480149 |
11 | 18a1a0a65189 |
12 | 841ab92a785 |
13 | 39970c847c6 |
14 | 1b0287c7b93 |
15 | d69ab9474e |
hex | 7853c4c5d5 |
516801480149 has 4 divisors (see below), whose sum is σ = 516804195264. Its totient is φ = 516798765036.
The previous prime is 516801480121. The next prime is 516801480203. The reversal of 516801480149 is 941084108615.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-516801480149 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (516801470149) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1048607 + ... + 1460540.
It is an arithmetic number, because the mean of its divisors is an integer number (129201048816).
Almost surely, 2516801480149 is an apocalyptic number.
It is an amenable number.
516801480149 is a deficient number, since it is larger than the sum of its proper divisors (2715115).
516801480149 is a wasteful number, since it uses less digits than its factorization.
516801480149 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2715114.
The product of its (nonzero) digits is 276480, while the sum is 47.
The spelling of 516801480149 in words is "five hundred sixteen billion, eight hundred one million, four hundred eighty thousand, one hundred forty-nine".
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