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516801480149 = 2059672509147
BaseRepresentation
bin1111000010100111100…
…01001100010111010101
31211101221210011100010002
413201103301030113111
531431402134331044
61033225413141045
752223552046443
oct7412361142725
91741853140102
10516801480149
1118a1a0a65189
12841ab92a785
1339970c847c6
141b0287c7b93
15d69ab9474e
hex7853c4c5d5

516801480149 has 4 divisors (see below), whose sum is σ = 516804195264. Its totient is φ = 516798765036.

The previous prime is 516801480121. The next prime is 516801480203. The reversal of 516801480149 is 941084108615.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-516801480149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (516801470149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1048607 + ... + 1460540.

It is an arithmetic number, because the mean of its divisors is an integer number (129201048816).

Almost surely, 2516801480149 is an apocalyptic number.

It is an amenable number.

516801480149 is a deficient number, since it is larger than the sum of its proper divisors (2715115).

516801480149 is a wasteful number, since it uses less digits than its factorization.

516801480149 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2715114.

The product of its (nonzero) digits is 276480, while the sum is 47.

The spelling of 516801480149 in words is "five hundred sixteen billion, eight hundred one million, four hundred eighty thousand, one hundred forty-nine".

Divisors: 1 205967 2509147 516801480149