Base | Representation |
---|---|
bin | 100101100110110100010… |
… | …1010100000010110111011 |
3 | 200022010001201211100201011 |
4 | 1023031220222200112323 |
5 | 1134140244004131024 |
6 | 14554231154334351 |
7 | 1042263523654213 |
oct | 113155052402673 |
9 | 20263051740634 |
10 | 5168601630139 |
11 | 1712a9a969762 |
12 | 6b586228a3b7 |
13 | 2b65213c085c |
14 | 13c239813243 |
15 | 8e6a93ea094 |
hex | 4b368aa05bb |
5168601630139 has 2 divisors, whose sum is σ = 5168601630140. Its totient is φ = 5168601630138.
The previous prime is 5168601630109. The next prime is 5168601630149. The reversal of 5168601630139 is 9310361068615.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5168601630139 - 223 = 5168593241531 is a prime.
It is a super-2 number, since 2×51686016301392 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5168601630092 and 5168601630101.
It is not a weakly prime, because it can be changed into another prime (5168601630109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2584300815069 + 2584300815070.
It is an arithmetic number, because the mean of its divisors is an integer number (2584300815070).
Almost surely, 25168601630139 is an apocalyptic number.
5168601630139 is a deficient number, since it is larger than the sum of its proper divisors (1).
5168601630139 is an equidigital number, since it uses as much as digits as its factorization.
5168601630139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 699840, while the sum is 49.
The spelling of 5168601630139 in words is "five trillion, one hundred sixty-eight billion, six hundred one million, six hundred thirty thousand, one hundred thirty-nine".
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