Base | Representation |
---|---|
bin | 100101100111000101010… |
… | …0110010001111001000011 |
3 | 200022011112102002200111221 |
4 | 1023032022212101321003 |
5 | 1134142430230311101 |
6 | 14554403453015511 |
7 | 1042313606043064 |
oct | 113161246217103 |
9 | 20264472080457 |
10 | 5169170947651 |
11 | 17132622703a7 |
12 | 6b59a0a84597 |
13 | 2b65b2335919 |
14 | 13c29129056b |
15 | 8e6de3a6aa1 |
hex | 4b38a991e43 |
5169170947651 has 2 divisors, whose sum is σ = 5169170947652. Its totient is φ = 5169170947650.
The previous prime is 5169170947571. The next prime is 5169170947657. The reversal of 5169170947651 is 1567490719615.
5169170947651 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5169170947651 - 213 = 5169170939459 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5169170947651.
It is not a weakly prime, because it can be changed into another prime (5169170947657) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2584585473825 + 2584585473826.
It is an arithmetic number, because the mean of its divisors is an integer number (2584585473826).
Almost surely, 25169170947651 is an apocalyptic number.
5169170947651 is a deficient number, since it is larger than the sum of its proper divisors (1).
5169170947651 is an equidigital number, since it uses as much as digits as its factorization.
5169170947651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14288400, while the sum is 61.
The spelling of 5169170947651 in words is "five trillion, one hundred sixty-nine billion, one hundred seventy million, nine hundred forty-seven thousand, six hundred fifty-one".
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