Base | Representation |
---|---|
bin | 1001101000101001… |
… | …00000101001001001 |
3 | 111100111110101111212 |
4 | 10310110200221021 |
5 | 41043211242423 |
6 | 2213142102505 |
7 | 242120504234 |
oct | 46424405111 |
9 | 14314411455 |
10 | 5172759113 |
11 | 2214984535 |
12 | 100441aa35 |
13 | 645898a12 |
14 | 370dd241b |
15 | 2041ce578 |
hex | 134520a49 |
5172759113 has 2 divisors, whose sum is σ = 5172759114. Its totient is φ = 5172759112.
The previous prime is 5172759103. The next prime is 5172759143. The reversal of 5172759113 is 3119572715.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4718728249 + 454030864 = 68693^2 + 21308^2 .
It is a cyclic number.
It is not a de Polignac number, because 5172759113 - 216 = 5172693577 is a prime.
It is a super-2 number, since 2×51727591132 = 53514873682249093538, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5172759103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2586379556 + 2586379557.
It is an arithmetic number, because the mean of its divisors is an integer number (2586379557).
Almost surely, 25172759113 is an apocalyptic number.
It is an amenable number.
5172759113 is a deficient number, since it is larger than the sum of its proper divisors (1).
5172759113 is an equidigital number, since it uses as much as digits as its factorization.
5172759113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 66150, while the sum is 41.
The square root of 5172759113 is about 71921.8959218957. The cubic root of 5172759113 is about 1729.4476404930.
The spelling of 5172759113 in words is "five billion, one hundred seventy-two million, seven hundred fifty-nine thousand, one hundred thirteen".
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