Base | Representation |
---|---|
bin | 110000001100100101… |
… | …101011011010110001 |
3 | 11221120121021121020022 |
4 | 300030211223122301 |
5 | 1321441201430223 |
6 | 35435103253225 |
7 | 3511301431625 |
oct | 601445533261 |
9 | 157517247208 |
10 | 51750811313 |
11 | 1aa46a90553 |
12 | a0432aa215 |
13 | 4b596c9a56 |
14 | 270d081185 |
15 | 152d433ac8 |
hex | c0c96b6b1 |
51750811313 has 2 divisors, whose sum is σ = 51750811314. Its totient is φ = 51750811312.
The previous prime is 51750811267. The next prime is 51750811327. The reversal of 51750811313 is 31311805715.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50610601024 + 1140210289 = 224968^2 + 33767^2 .
It is a cyclic number.
It is not a de Polignac number, because 51750811313 - 230 = 50677069489 is a prime.
It is not a weakly prime, because it can be changed into another prime (51750841313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25875405656 + 25875405657.
It is an arithmetic number, because the mean of its divisors is an integer number (25875405657).
Almost surely, 251750811313 is an apocalyptic number.
It is an amenable number.
51750811313 is a deficient number, since it is larger than the sum of its proper divisors (1).
51750811313 is an equidigital number, since it uses as much as digits as its factorization.
51750811313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12600, while the sum is 35.
The spelling of 51750811313 in words is "fifty-one billion, seven hundred fifty million, eight hundred eleven thousand, three hundred thirteen".
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