Base | Representation |
---|---|
bin | 1111000100011101111… |
… | …10101100001100011011 |
3 | 1211111112000101222111002 |
4 | 13202032332230030123 |
5 | 31440420441433024 |
6 | 1033512141055215 |
7 | 52260303545024 |
oct | 7421676541433 |
9 | 1744460358432 |
10 | 517794874139 |
11 | 18a660786854 |
12 | 8442855750b |
13 | 39a9ba1abba |
14 | 1b0c06d5c4b |
15 | d707ebd6ae |
hex | 788efac31b |
517794874139 has 2 divisors, whose sum is σ = 517794874140. Its totient is φ = 517794874138.
The previous prime is 517794874127. The next prime is 517794874147. The reversal of 517794874139 is 931478497715.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 517794874139 - 216 = 517794808603 is a prime.
It is a super-2 number, since 2×5177948741392 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (517794874339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258897437069 + 258897437070.
It is an arithmetic number, because the mean of its divisors is an integer number (258897437070).
Almost surely, 2517794874139 is an apocalyptic number.
517794874139 is a deficient number, since it is larger than the sum of its proper divisors (1).
517794874139 is an equidigital number, since it uses as much as digits as its factorization.
517794874139 is an evil number, because the sum of its binary digits is even.
The product of its digits is 53343360, while the sum is 65.
The spelling of 517794874139 in words is "five hundred seventeen billion, seven hundred ninety-four million, eight hundred seventy-four thousand, one hundred thirty-nine".
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