Base | Representation |
---|---|
bin | 110000001111000111… |
… | …110100010001010111 |
3 | 11221200120021000012100 |
4 | 300033013310101113 |
5 | 1322033042034103 |
6 | 35443222253143 |
7 | 3512325625041 |
oct | 601707642127 |
9 | 157616230170 |
10 | 51793314903 |
11 | 1aa68a81090 |
12 | a0555871b3 |
13 | 4b6545bcc5 |
14 | 2714986a91 |
15 | 153202c5a3 |
hex | c0f1f4457 |
51793314903 has 24 divisors (see below), whose sum is σ = 83604293136. Its totient is φ = 30624278400.
The previous prime is 51793314887. The next prime is 51793314919. The reversal of 51793314903 is 30941339715.
51793314903 is a `hidden beast` number, since 517 + 9 + 33 + 14 + 90 + 3 = 666.
51793314903 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (51793314887) and next prime (51793314919).
It is not a de Polignac number, because 51793314903 - 24 = 51793314887 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51793314973) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6376000 + ... + 6384117.
It is an arithmetic number, because the mean of its divisors is an integer number (3483512214).
Almost surely, 251793314903 is an apocalyptic number.
51793314903 is a deficient number, since it is larger than the sum of its proper divisors (31810978233).
51793314903 is a wasteful number, since it uses less digits than its factorization.
51793314903 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12760175 (or 12760172 counting only the distinct ones).
The product of its (nonzero) digits is 306180, while the sum is 45.
The spelling of 51793314903 in words is "fifty-one billion, seven hundred ninety-three million, three hundred fourteen thousand, nine hundred three".
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