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51981343 = 317163979
BaseRepresentation
bin1100011001001…
…0110000011111
310121210220222221
43012102300133
5101301400333
65054050211
71200556051
oct306226037
9117726887
1051981343
1127384397
12154a9967
13aa001bb
146c918d1
15486bd2d
hex3192c1f

51981343 has 4 divisors (see below), whose sum is σ = 52145640. Its totient is φ = 51817048.

The previous prime is 51981341. The next prime is 51981361. The reversal of 51981343 is 34318915.

51981343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 51981343 - 21 = 51981341 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51981299 and 51981308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51981341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81673 + ... + 82306.

It is an arithmetic number, because the mean of its divisors is an integer number (13036410).

Almost surely, 251981343 is an apocalyptic number.

51981343 is a deficient number, since it is larger than the sum of its proper divisors (164297).

51981343 is a wasteful number, since it uses less digits than its factorization.

51981343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 164296.

The product of its digits is 12960, while the sum is 34.

The square root of 51981343 is about 7209.8088046771. The cubic root of 51981343 is about 373.2064709441.

The spelling of 51981343 in words is "fifty-one million, nine hundred eighty-one thousand, three hundred forty-three".

Divisors: 1 317 163979 51981343