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52003133201177 is a prime number
BaseRepresentation
bin10111101001011111011000…
…10010000001101100011001
320211010110011202200020002222
423310233230102001230121
523304004404044414202
6302333524245433425
713645050055614404
oct1364575422015431
9224113152606088
1052003133201177
111562a44aa78334
1259ba68010b875
132302b4a138432
14cbad72254d3b
15602ac2c434a2
hex2f4bec481b19

52003133201177 has 2 divisors, whose sum is σ = 52003133201178. Its totient is φ = 52003133201176.

The previous prime is 52003133201111. The next prime is 52003133201197. The reversal of 52003133201177 is 77110233130025.

52003133201177 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40571052550681 + 11432080650496 = 6369541^2 + 3381136^2 .

It is a cyclic number.

It is not a de Polignac number, because 52003133201177 - 218 = 52003132939033 is a prime.

It is not a weakly prime, because it can be changed into another prime (52003133201197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26001566600588 + 26001566600589.

It is an arithmetic number, because the mean of its divisors is an integer number (26001566600589).

Almost surely, 252003133201177 is an apocalyptic number.

It is an amenable number.

52003133201177 is a deficient number, since it is larger than the sum of its proper divisors (1).

52003133201177 is an equidigital number, since it uses as much as digits as its factorization.

52003133201177 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26460, while the sum is 35.

The spelling of 52003133201177 in words is "fifty-two trillion, three billion, one hundred thirty-three million, two hundred one thousand, one hundred seventy-seven".