Base | Representation |
---|---|
bin | 110000011100001101… |
… | …000010100010101001 |
3 | 11222020212020101112011 |
4 | 300130031002202221 |
5 | 1323010233203011 |
6 | 35521102315521 |
7 | 3520632254665 |
oct | 603415024251 |
9 | 158225211464 |
10 | 52012787881 |
11 | 2007095440a |
12 | a0b6b88ba1 |
13 | 4b9ba73882 |
14 | 2735b978a5 |
15 | 1546431621 |
hex | c1c3428a9 |
52012787881 has 2 divisors, whose sum is σ = 52012787882. Its totient is φ = 52012787880.
The previous prime is 52012787747. The next prime is 52012787933. The reversal of 52012787881 is 18878721025.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42576608281 + 9436179600 = 206341^2 + 97140^2 .
It is a cyclic number.
It is not a de Polignac number, because 52012787881 - 223 = 52004399273 is a prime.
It is a super-2 number, since 2×520127878812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (52012787081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26006393940 + 26006393941.
It is an arithmetic number, because the mean of its divisors is an integer number (26006393941).
Almost surely, 252012787881 is an apocalyptic number.
It is an amenable number.
52012787881 is a deficient number, since it is larger than the sum of its proper divisors (1).
52012787881 is an equidigital number, since it uses as much as digits as its factorization.
52012787881 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 501760, while the sum is 49.
The spelling of 52012787881 in words is "fifty-two billion, twelve million, seven hundred eighty-seven thousand, eight hundred eighty-one".
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