Base | Representation |
---|---|
bin | 1100011001101… |
… | …0110000100001 |
3 | 10121212120221122 |
4 | 3012122300201 |
5 | 101303422423 |
6 | 5054502025 |
7 | 1201053434 |
oct | 306326041 |
9 | 117776848 |
10 | 52014113 |
11 | 273a6a78 |
12 | 15504915 |
13 | aa120a8 |
14 | 6c9d81b |
15 | 48768c8 |
hex | 319ac21 |
52014113 has 2 divisors, whose sum is σ = 52014114. Its totient is φ = 52014112.
The previous prime is 52014097. The next prime is 52014121. The reversal of 52014113 is 31141025.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49168144 + 2845969 = 7012^2 + 1687^2 .
It is a cyclic number.
It is not a de Polignac number, because 52014113 - 24 = 52014097 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 52014091 and 52014100.
It is not a weakly prime, because it can be changed into another prime (52014163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26007056 + 26007057.
It is an arithmetic number, because the mean of its divisors is an integer number (26007057).
Almost surely, 252014113 is an apocalyptic number.
It is an amenable number.
52014113 is a deficient number, since it is larger than the sum of its proper divisors (1).
52014113 is an equidigital number, since it uses as much as digits as its factorization.
52014113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 17.
The square root of 52014113 is about 7212.0810450244. The cubic root of 52014113 is about 373.2848798901.
Adding to 52014113 its reverse (31141025), we get a palindrome (83155138).
The spelling of 52014113 in words is "fifty-two million, fourteen thousand, one hundred thirteen".
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