Base | Representation |
---|---|
bin | 100101110110001001111… |
… | …1110011111001000100011 |
3 | 200102021002022012111122011 |
4 | 1023230103332133020203 |
5 | 1140210223334334021 |
6 | 15021315453453351 |
7 | 1044541011053161 |
oct | 113542376371043 |
9 | 20367068174564 |
10 | 5201540543011 |
11 | 1725a6303a4aa |
12 | 7001154a1257 |
13 | 2b96705cc447 |
14 | 13da822c2231 |
15 | 9048604cde1 |
hex | 4bb13f9f223 |
5201540543011 has 2 divisors, whose sum is σ = 5201540543012. Its totient is φ = 5201540543010.
The previous prime is 5201540542999. The next prime is 5201540543083. The reversal of 5201540543011 is 1103450451025.
5201540543011 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5201540543011 - 231 = 5199393059363 is a prime.
It is a super-2 number, since 2×52015405430112 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5201540643011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2600770271505 + 2600770271506.
It is an arithmetic number, because the mean of its divisors is an integer number (2600770271506).
Almost surely, 25201540543011 is an apocalyptic number.
5201540543011 is a deficient number, since it is larger than the sum of its proper divisors (1).
5201540543011 is an equidigital number, since it uses as much as digits as its factorization.
5201540543011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 5201540543011 its reverse (1103450451025), we get a palindrome (6304990994036).
The spelling of 5201540543011 in words is "five trillion, two hundred one billion, five hundred forty million, five hundred forty-three thousand, eleven".
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