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520344113 is a prime number
BaseRepresentation
bin11111000000111…
…101001000110001
31100021010012221012
4133000331020301
52031202002423
6123344440305
715615565142
oct3700751061
91307105835
10520344113
112477a2263
12126319095
1383a59033
144d16dac9
1530a36078
hex1f03d231

520344113 has 2 divisors, whose sum is σ = 520344114. Its totient is φ = 520344112.

The previous prime is 520344067. The next prime is 520344131. The reversal of 520344113 is 311443025.

Together with next prime (520344131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 470542864 + 49801249 = 21692^2 + 7057^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-520344113 is a prime.

It is not a weakly prime, because it can be changed into another prime (520344133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 260172056 + 260172057.

It is an arithmetic number, because the mean of its divisors is an integer number (260172057).

Almost surely, 2520344113 is an apocalyptic number.

It is an amenable number.

520344113 is a deficient number, since it is larger than the sum of its proper divisors (1).

520344113 is an equidigital number, since it uses as much as digits as its factorization.

520344113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 520344113 is about 22811.0524307845. The cubic root of 520344113 is about 804.3224951687.

Adding to 520344113 its reverse (311443025), we get a palindrome (831787138).

The spelling of 520344113 in words is "five hundred twenty million, three hundred forty-four thousand, one hundred thirteen".