Base | Representation |
---|---|
bin | 111011001010011010110101… |
… | …0100011001000000001100010 |
3 | 2112020120220020022011001120212 |
4 | 1312110311222203020001202 |
5 | 1021202224233000401032 |
6 | 5042445052042334122 |
7 | 214420524205000313 |
oct | 16624655243100142 |
9 | 2466526208131525 |
10 | 520401500012642 |
11 | 1408a8044a10976 |
12 | 4a4493694ba342 |
13 | 1944b85ccb09b1 |
14 | 92717d1b8460a |
15 | 4026c85bcabb2 |
hex | 1d94d6a8c8062 |
520401500012642 has 4 divisors (see below), whose sum is σ = 780602250018966. Its totient is φ = 260200750006320.
The previous prime is 520401500012599. The next prime is 520401500012689. The reversal of 520401500012642 is 246210005104025.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 364428901780441 + 155972598232201 = 19090021^2 + 12488899^2 .
It is a junction number, because it is equal to n+sod(n) for n = 520401500012599 and 520401500012608.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 130100375003159 + ... + 130100375003162.
Almost surely, 2520401500012642 is an apocalyptic number.
520401500012642 is a deficient number, since it is larger than the sum of its proper divisors (260200750006324).
520401500012642 is a wasteful number, since it uses less digits than its factorization.
520401500012642 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 260200750006323.
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 520401500012642 its reverse (246210005104025), we get a palindrome (766611505116667).
The spelling of 520401500012642 in words is "five hundred twenty trillion, four hundred one billion, five hundred million, twelve thousand, six hundred forty-two".
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