Base | Representation |
---|---|
bin | 110000011111010110… |
… | …101111101101100000 |
3 | 11222101112201202201000 |
4 | 300133112233231200 |
5 | 1323112302220330 |
6 | 35530231512000 |
7 | 3522143561211 |
oct | 603726575540 |
9 | 158345652630 |
10 | 52065663840 |
11 | 20098789953 |
12 | a110828600 |
13 | 4ba99c8018 |
14 | 273cbdd408 |
15 | 154adc8560 |
hex | c1f5afb60 |
52065663840 has 192 divisors, whose sum is σ = 186675088320. Its totient is φ = 13545492480.
The previous prime is 52065663821. The next prime is 52065663889. The reversal of 52065663840 is 4836656025.
52065663840 is a `hidden beast` number, since 5 + 2 + 0 + 6 + 5 + 6 + 638 + 4 + 0 = 666.
It is a super-3 number, since 3×520656638403 (a number of 33 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 30142 + ... + 324098.
It is an arithmetic number, because the mean of its divisors is an integer number (972266085).
Almost surely, 252065663840 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 52065663840, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (93337544160).
52065663840 is an abundant number, since it is smaller than the sum of its proper divisors (134609424480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
52065663840 is a wasteful number, since it uses less digits than its factorization.
52065663840 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 294022 (or 294008 counting only the distinct ones).
The product of its (nonzero) digits is 1036800, while the sum is 45.
The spelling of 52065663840 in words is "fifty-two billion, sixty-five million, six hundred sixty-three thousand, eight hundred forty".
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