Base | Representation |
---|---|
bin | 110000100000110010… |
… | …000011101010000011 |
3 | 11222110012202212211021 |
4 | 300200302003222003 |
5 | 1323134414210033 |
6 | 35532444530311 |
7 | 3522554204623 |
oct | 604062035203 |
9 | 158405685737 |
10 | 52089600643 |
11 | 20100248a33 |
12 | a118850997 |
13 | 4bb1959302 |
14 | 2742070883 |
15 | 154d055b2d |
hex | c20c83a83 |
52089600643 has 2 divisors, whose sum is σ = 52089600644. Its totient is φ = 52089600642.
The previous prime is 52089600611. The next prime is 52089600649. The reversal of 52089600643 is 34600698025.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52089600643 - 25 = 52089600611 is a prime.
It is a super-4 number, since 4×520896006434 (a number of 44 digits) contains 4444 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 52089600643.
It is not a weakly prime, because it can be changed into another prime (52089600649) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26044800321 + 26044800322.
It is an arithmetic number, because the mean of its divisors is an integer number (26044800322).
Almost surely, 252089600643 is an apocalyptic number.
52089600643 is a deficient number, since it is larger than the sum of its proper divisors (1).
52089600643 is an equidigital number, since it uses as much as digits as its factorization.
52089600643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 43.
The spelling of 52089600643 in words is "fifty-two billion, eighty-nine million, six hundred thousand, six hundred forty-three".
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