Base | Representation |
---|---|
bin | 110000100000110010… |
… | …010011101010010001 |
3 | 11222110012220012202001 |
4 | 300200302103222101 |
5 | 1323134423304233 |
6 | 35532450154001 |
7 | 3522554600005 |
oct | 604062235221 |
9 | 158405805661 |
10 | 52089666193 |
11 | 20100293204 |
12 | a118882901 |
13 | 4bb19800b6 |
14 | 274208a705 |
15 | 154d06a27d |
hex | c20c93a91 |
52089666193 has 2 divisors, whose sum is σ = 52089666194. Its totient is φ = 52089666192.
The previous prime is 52089666179. The next prime is 52089666197. The reversal of 52089666193 is 39166698025.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42100063489 + 9989602704 = 205183^2 + 99948^2 .
It is a cyclic number.
It is not a de Polignac number, because 52089666193 - 213 = 52089658001 is a prime.
It is a super-2 number, since 2×520896661932 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (52089666197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26044833096 + 26044833097.
It is an arithmetic number, because the mean of its divisors is an integer number (26044833097).
Almost surely, 252089666193 is an apocalyptic number.
It is an amenable number.
52089666193 is a deficient number, since it is larger than the sum of its proper divisors (1).
52089666193 is an equidigital number, since it uses as much as digits as its factorization.
52089666193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4199040, while the sum is 55.
The spelling of 52089666193 in words is "fifty-two billion, eighty-nine million, six hundred sixty-six thousand, one hundred ninety-three".
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