Base | Representation |
---|---|
bin | 1001101101000101… |
… | …11101110101001001 |
3 | 111110002201122211222 |
4 | 10312202331311021 |
5 | 41132241244423 |
6 | 2220554331425 |
7 | 243053100665 |
oct | 46642756511 |
9 | 14402648758 |
10 | 5210103113 |
11 | 2233a70646 |
12 | 1014a29b75 |
13 | 650542667 |
14 | 375d538a5 |
15 | 2076093c8 |
hex | 1368bdd49 |
5210103113 has 2 divisors, whose sum is σ = 5210103114. Its totient is φ = 5210103112.
The previous prime is 5210103061. The next prime is 5210103121. The reversal of 5210103113 is 3113010125.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2653486144 + 2556616969 = 51512^2 + 50563^2 .
It is a cyclic number.
It is not a de Polignac number, because 5210103113 - 216 = 5210037577 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5210103091 and 5210103100.
It is not a weakly prime, because it can be changed into another prime (5210100113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2605051556 + 2605051557.
It is an arithmetic number, because the mean of its divisors is an integer number (2605051557).
Almost surely, 25210103113 is an apocalyptic number.
It is an amenable number.
5210103113 is a deficient number, since it is larger than the sum of its proper divisors (1).
5210103113 is an equidigital number, since it uses as much as digits as its factorization.
5210103113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 17.
The square root of 5210103113 is about 72181.0440004853. The cubic root of 5210103113 is about 1733.5994991123.
Adding to 5210103113 its reverse (3113010125), we get a palindrome (8323113238).
The spelling of 5210103113 in words is "five billion, two hundred ten million, one hundred three thousand, one hundred thirteen".
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